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Understanding the Exponential Time Hypothesis, and OpenAI's claim it is false

No. The claimed running time, roughly 2n/log⁡n2^{n/\sqrt{\log n}}2n/logn​, is still far above any polynomial, and ETH failing says nothing either way about P vs NP. The paper itself notes that its result doesn't imply s…

Hacker News 最新gravity132026/10/27 · 昨天1 分钟阅读

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No. The claimed running time, roughly 2n/log⁡n2^{n/\sqrt{\log n}}2n/logn​, is still far above any polynomial, and ETH failing says nothing either way about P vs NP. The paper itself notes that its result doesn't imply subexponential algorithms for general NP problems, because the usual translations between problems can blow up the input size.

本条为导读摘要,完整论述请以原文为准。

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